A - the total value of the first two chosen coins is $0.26
B - third chosen coin is a penny
[tex]P(B|A)=\dfrac{P(A \cap B)}{P(A)}\\\\
|\Omega|=14\cdot13=182\\
|A|=2\cdot4\cdot2!=16\\
|A \cap B|=16\cdot3=48\\\\
P(A \cap B)=\dfrac{48}{182\cdot12}=\dfrac{2}{91}\\
P(A)=\dfrac{16}{182}=\dfrac{8}{91}\\\\
P(B|A)=\dfrac{\dfrac{2}{91}}{\dfrac{8}{91}}=\dfrac{2}{91}\cdot\dfrac{91}{8}=\dfrac{1}{4}
[/tex]
