Respuesta :

ag6567
The axis of symmetry for 10x^2-3x-1 would be x=3/20
The x=coordinate of the axis of symmetry of this vertical parabola is given by

x = -b / (2a), and here a= 10 and b= -3.  Then,

x = -(-3) / [2*10], or    x = 3/20.