The oxidation state of potassium ion K = +1 The oxidation state of oxygen ion O = -2 So, the oxidation state of O2 is = -2 x 2 = -4 Since, KBrO2 is neutral so, (+1) + (x) + (-4) = Zero -3 + X = Zero So, X = +3 The oxidation state of individual bromine atom in KBrO2 is +3
