contestada

What is the absolute pressure at a depth of 9.31 m below the surface of a deep lake? take 1.01 × 105 pa as atmospheric pressure?

Respuesta :

Stevin's law:
P=dgh+p0
Where p0 is the atmospheric pressure (1.01*10^5 Pa);
d is the liquid density (water, 1000 kg/m³)
g is the gravity acceleration (9.8 m/s²);
h is the depth (9.31m).
P=(1000)(9.8)(9.31)+101000=192238 Pa

Otras preguntas