A party rental company has chairs and tables for rent. The total cost to rent 3 chairs and 2 tables is $18. The total cost to rent 5 chairs and 6 tables is $48. What is the cost to rent each chair and each table
Create two equations with the given information. Solve for one variable in equation one. Substitute that answer in equation two. Then you can solve for the needed information. 3c+2t=$18 5c+6t=$48
3c+2t=18 Subtract 2c from both sides 3c=18-2t Divide both sides by 3 c=(18-2t)/3
Substitute the value for c in equation two: 5c+6t=$48 5((18-2t)/3)+6t=48 (90-10t)/3+6t=48 Multiply everything by 3 to eliminate fraction (3)((90-10t)/3)+(3)(6t)=(3)(48) 90-10t+18t=144 90+8t=144 Subtract 90 from both sides 8t=54 Divide both sides by 8 t=$6.75 cost for table
Substitute the t value to solve for c: 3c+2t=18 3c+2(6.75)=18 3c+13.50=18 3c=4.50 c=$1.50 chair cost
