meyasmith
meyasmith
06-02-2018
Chemistry
contestada
The mole in 196.5 g of Zn(NO3)2
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faitharmour
faitharmour
06-02-2018
Zn(NO3)2 = 65.38+ 2{14+ 3(16)} = A
196.5 gr ^ 1/A = your answer mole
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