Respuesta :

calculista
f(x) = log2x- -------> y=log2x-------- > 2^(y)=x  (I)

therefore

in the equation  2^(2y) = 6---- >(2^(y))^2 = 6  (II)

(I) in (II)

((x))^2 = 6-----------------x=2.45

using a graphic tool
see graphic attached

for x=2.45 the value of y approximate is 1.2928
Ver imagen calculista

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