A kite has a square base with dimensions of 4 feet by 4 feet. what is the length of one of the diagonal crossbars that will be needed to stabilize the kite?

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The diagonal crossbar would create a hypotenuse so you can use Pythagorean Theorem of a^2 + b^2 = c^2. The two '4 feet' lengths would be the legs (a and b). 

So now just plug in: 4^2 + 4^2 = c^2. Simplify to 16 + 16 = c^2. Simplify again to 32 = c^2. Square root both sides to isolate the variable c. to get C = sq[tex]4 \sqrt{2} [/tex]. 

The length of one of the diagonal crossbars is [tex]4 \sqrt{2} [/tex] feet.  

The length of one of the diagonal crossbars that will be needed to stabilize the kite is 4√2 feet or 5.65 feet.

What is a right-angle triangle?

It is defined as a triangle in which one angle is 90 degrees and the other two angles are acute angles. In a right-angled triangle, the name of the sides are hypotenuse, perpendicular, and base.

The diagonal will create a hypotenuse of a right angle triangle.

From the Pythagoras theorem:

[tex]\rm Hypotenuse^2=Perpendicular^2+Base^2[/tex]

We have the same length of perpendicular and base, which is 4 feet.

Hypotenuse = d feet

[tex]\rm d^2=4^2+4^2\\\\d^2 = 2\times 4^2[/tex]

After calculating;

d = 4√2 feet or

d = 5.65 feet

Thus, the length of one of the diagonal crossbars that will be needed to stabilize the kite is 4√2 feet or 5.65 feet.

Learn more about the right angle triangle here:

brainly.com/question/3770177

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