Respuesta :

[tex]\bf \textit{arc's length}\\\\ s=r\theta \quad \begin{cases} r=radius\\ \theta =angle~in\\ \qquad radians\\ ------\\ s=10\\ \theta =\frac{2\pi }{3} \end{cases}\implies 10=r\cdot \cfrac{2\pi }{3}\implies \cfrac{30}{2\pi }=r\implies \cfrac{15}{\pi }=r[/tex]

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