Respuesta :
From the balanced equation:
1mol C3H8 requires 5mol O2 for combustion
Molar mass C3H8 = 44g/mol
8.8g C3H8 = 8.8/44 = 0.2mol C3H8
This will require 5*0.2 = 1.0mol O2
Molar mass O2 = 32g/mol
Therefore 32g of O2 required.
1mol C3H8 requires 5mol O2 for combustion
Molar mass C3H8 = 44g/mol
8.8g C3H8 = 8.8/44 = 0.2mol C3H8
This will require 5*0.2 = 1.0mol O2
Molar mass O2 = 32g/mol
Therefore 32g of O2 required.
There are 32 gram of oxygen molecule will be required to burn [tex]C_{3} H_{8}[/tex].
What is oxygen?
The air contains significant amounts of oxygen, an invisible gas. The chemical element with the atomic number 8 and symbol O being called oxygen. It belongs to the periodic table's chalcogen group, would be a very reactive nonmetal, and is also an oxidizing agent that easily produces oxides with many of these elements as well as other compounds.
What is molecule?
A molecule is the smallest unit of any material that is composed of one or more elements that was capable of existing independently while maintaining all of the substance's physical as well as chemical properties. Further atom division occurs within molecules. For instance, the symbols for the oxygen atom and molecule are O and [tex]O_{2}[/tex], respectively.
The combustion reaction can be written as:
[tex]C_{3} H_{8} + 5O_{2}[/tex] → [tex]3CO_{2} + 4H_{2} O[/tex].
It can be seen that 1 mole of [tex]C_{3} H_{8}[/tex] = 5 Mol oxygen ( [tex]O_{2}[/tex] ) for combustion.
Molar mass of [tex]C_{3} H_{8}[/tex]. = 8.8 / 44 = 0.2 mol [tex]C_{3} H_{8}[/tex].
It will be require 5 × 0.2 = 1 mol [tex]O_{2}[/tex].
Molar mass of oxygen ([tex]O_{2}[/tex] )= 32 g/mol.
That's why 32 g of oxygen [tex]O_{2}[/tex] will be required .
Therefore, there are 32 gram of oxygen molecule will be required to burn [tex]C_{3} H_{8}[/tex].
To know more about oxygen
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