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A scientist is cooling liquid at a steady rate. The temperature of the liquid changed by −82 1/2 °C over 2 1/5 minutes. What was the temperature change after 1 minute? Enter your answer as a mixed number, in simplest form.

Respuesta :

Ratio: Degree Change/Time

-82 1/2°C/2 1/5 minutes = X°C/1 minute

Cross Multiply: a/b=x/d ... ad=bx ... x=ad/b

Whereas X is over 1, you already have
X = (-82 1/2)/(2 1/5) so divide

X = 82.5/2.2 = 37.5
Answer = -37 1/2°C

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