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a cliff diver drops from rest to the water below. how many seconds does it take for the diver to go from 0 to 60. that is to go from 0mph to 60mph

Respuesta :

u = 0, initial vertical velocity
v = 60 mph = 88 ft/s

Ignore air resistance and take g = 32 ft/s².
It t = time to attain 60 mph, then
(88 ft/s) = (32 ft/s²)*(t s)
t = 88/32 = 2.75 s

Answer: 2.75 s

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