Respuesta :

mreijepatmat
log₂(6x) - log₂(√x) = 2

log₂[6x/√x] = 2, let's rewrite it in terms of exponent:

(remember : ㏒₂(x) = a  (in exponential form) → x = 2ᵃ

6x/√x = 2²

6x/√x = 4, square both sides:
36x²/x = 16 .Simplify:

36x = 16 and x = 16/36 . So x = 4/9

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