A rhombus is inscribed in a rectangle that is w meters wide with a perimeter of 4444 m. each vertex of the rhombus is a midpoint of a side of the rectangle. express the area of the rhombus as a function of the? rectangle's width.

Respuesta :

ulhasj
Given description, the area of the rhombus is 1/2 the area of the rectangle it is in.

W = W

Perimeter = 4444 = 2*H + 2*W
H = (4444 - 2*W)/2

Area = 1/2*H*W
Area = 1/2*(4444 - 2*W)/2*W
Area = 4444*W - 2*W^2