SavannahThomas87 SavannahThomas87

10-06-2017
Mathematics

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[cos^-1(4/2)-3.14/2]

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10-06-2017

cos^-1(4/2)=cos^-1(2)-pi/2
The inverse cosine function has a domain of [-1,1], and -2 is outside of that range, so there is no solution
Unless you meant cos^-1, as in 1/cos or sec, in which case cos(1/2)-pi/2
This would be pi/3-pi/2=-pi/6

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