We have 5 Republican Candidates and 6 Democratic Candidates
We have a total 11 candidates to choose from
First pick of Democratic Candidates = 6/11
Second pick of Democratic Candidates = 5/10
Third pick of Democratic Candidates = 4/9
Fourth pick of Democratic Candidates = 3/8
The probability of four Democratic candidates in the committee is
[tex] \frac{6}{11} [/tex]×[tex] \frac{5}{10} [/tex]×[tex] \frac{4}{9} [/tex]×[tex] \frac{3}{8} [/tex] = [tex] \frac{360}{7920} = \frac{1}{22} [/tex]
