If a 3.00-kg pendulum is 28.84 m long, then its period on earth is 10.773secs
The formula for calculating the period of the pendulum is expressed as:
[tex]T=2 \pi\sqrt{\frac{l}{g} }[/tex]
l is the length of the pendulum
g is the acceleration due to gravity
Given the following parameters
[tex]g =9.8m/s^2\\l = 28.84\\\pi = 3.14[/tex]
Substitute the given parameters into the formula:
[tex]T=2 (3.14)\sqrt{\frac{28.84}{9.8} }\\T=6.28\sqrt{2.94}\\T=6.28(1.715)\\T= 10.773secs[/tex]
Hence if a 3.00-kg pendulum is 28.84 m long, then its period on earth is 10.773secs
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