kieranherr
kieranherr
10-04-2017
Mathematics
contestada
How do i solve this? [tex]sec^2x+2secx[/tex]
Respuesta :
Аноним
Аноним
10-04-2017
sec x = a
sec^2 x + 2sec x = 0
a^2 + 2a = 0
a(a + 2) = 0
a = 0 or a + 2 = 0
a = -2
i.e. sec x = -2
1/cos x = -2
-2cos x = 1
cos x = -1/2
Hope I helped!
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