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Brian is solving the equation x2-3/4x=5. What value must be added to both sides of the equation to make the left side a perfect-square trinomial?

Respuesta :

ivanzud
divide 3/4 by 2 and then square it. 3/4/2=3/8 squared which is 9/64.
calculista

we have

[tex]x^{2} -\frac{3}{4}x=5[/tex]

Divide the term  [tex]\frac{3}{4}[/tex] by [tex]2[/tex] and then square it

[tex](\frac{(3/4)}{2})^{2}= \frac{9}{64}[/tex]

Add to both sides

[tex]x^{2} -\frac{3}{4}x+\frac{9}{64}=5+\frac{9}{64}[/tex]

Rewrite as perfect square

[tex](x-\frac{3}{8})^{2}=\frac{329}{64}[/tex]

therefore

the answer is

[tex]\frac{9}{64}[/tex]

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