Given: 19.2g of solute(NaOH) in 160L of solution.
Wanted: Molarity(M) of the solution
M = moles of solute/liters of solution
First, we need to turn the grams into moles of solute. By doing so, you need to find the molar mass of NaOH. Which is 39.997 g/mol.
moles of solute = 19.2g * 1 mol/39.997g
19.2/39.997 = moles of solute = 0.480
Now that we have the moles of solute, we can find out the molarity.
M= 0.480 moles of solute/160L = 0.003M
Answer: 0.003M
Hope this is helpful!
