Respuesta :
take 1/2 of linear coefient (1st degree)
that is p
p=1p
linear cofient is 1
1/2 of that is 1/2
square it to get 1/4
therefor the constant is 1/4
it factors to
[tex](p+ \frac{1}{2})^2 [/tex]
that is p
p=1p
linear cofient is 1
1/2 of that is 1/2
square it to get 1/4
therefor the constant is 1/4
it factors to
[tex](p+ \frac{1}{2})^2 [/tex]