blrowe
blrowe
07-03-2017
Mathematics
contestada
How would you solve k^2-5k+6=0
Respuesta :
Аноним
Аноним
07-03-2017
k2 + -5k + 6 = 0
6 + -5k + k2 = 0
6 + -5k + k2 = 0
Solving for variable 'k'.
Factor a trinomial. (2 + -1k)(3 + -1k) = 0 2 + -1k = 0
k = {2, 3}
hoped this helped i skipped some steps so you don't have to wait
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amazingmaddi
amazingmaddi
07-03-2017
k^2-5k+6=0
k^2-5k=-6
k-2.23k=2.44
1.23k=2.44
k=1.99
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