murawskik
murawskik
06-03-2017
Mathematics
contestada
Sec^4x-tan^4x=sec^2x+tan^2x
Respuesta :
LammettHash
LammettHash
06-03-2017
[tex]\sec^4x-\tan^4x=(\sec^2x-\tan^2)(\sec^2x+\tan^2x)=\sec^2x+\tan^2x[/tex]
since [tex]\tan^2x+1=\sec^2x[/tex].
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