By taking minimum perimeter the value of length and width will both be [tex]\sqrt{5A}[/tex].
Perimeter is basically the sum of all sides of a figure.
The perimeter of a rectangle is 2l + 2w where l = length and w = width of rectangle.
Since the perimeter needed in this question is minimum, the figure must be a square and not a rectangle. For a square, area = a^2
5A = a^2
a = l = w = [tex]\sqrt{5A}[/tex]
Hence, both the length and width are equal to [tex]\sqrt{5A}[/tex].
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