After 1 second, the bullet will be 100 m to the side and 5m downrange.
v = 100m/s
θ = 0°
g=—10 m/s^2
the x component is
x = vcos(θ)t
The y component is
y = vsin(θ)t+1/2gt^2
In 1 second, the distance traveled by the bullet is
x = 100cos(0°)⋅1
=100m
the bullet be 1 second later at the y components
y = 100sin(0°)⋅1+1/2(—10)⋅(1)^2
=0—5
=—5m
So after 1 second, the bullet will be 100 m to the side and 5m downrange.
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