a stock solution of potassium chloride has a concentration of 200.0gl. what volume of the stock solution is required to prepare a 2.00l solution with a concentration of 50.0gl?

Respuesta :

The equation M1V1 = M2V2 is used to solve problems related to dilution in chemistry

Given data in the question

intial concentration = 200 g/l

final concentration = 50 g/l

volume = 2.00 l

Now we know that

M1V1 = M2V2

where

M1 = initial concentration

M2 = concentration after mixing or diluting

V1 = initial volume,

V2 = total final volume

The equation M1V1 = M2V2 is used to solve problems related to dilution in chemistry

What is dilution?

It is process of decreasing the concentration of a solute in a solution, usually simply by mixing with more solvent like adding more water to solution.”

200 g/l × V = 50 g/l × 2

V = ( 50 × 2 ) / 200

= 0.5 L

Volume of stock required is 0.5L

Learn more about dilution at https://brainly.com/question/20709987

#SPJ4