If M is the midpoint of AB , B(-7,16) and M(-2,8) then coordinates of the missing endpoint A are (3,0).
As given in the question,
M is the midpoint of AB
Let coordinates of A(x₁ ,y₁) , B(x₂ ,y₂) and M(x ,y)
So,
x = (x₁ + x₂)/2
⇒-2 = (x₁ + (-7))/2
⇒ x₁ = 7-4
⇒x₁ =3
y = (y₁+ y₂)/2
⇒8 = (y₁ +16)/2
⇒ y₁ = 16-16
⇒ y₁ =0
Therefore, if M is the midpoint of AB , B(-7,16) and M(-2,8) then coordinates of the missing endpoint A are (3,0).
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