A recent survey by the American Automobile Association showed that a family of two adults and two children on vacation in the United States will pay an average of $247 per day for food and lodging with a standard deviation of $60 per day. You can compute the mean food and lodging cost of a 10-day vacation by multiplying the per-day mean by 10. The standard deviation for the 10-day vacation can be found by multiplying by 10 also.
Note: Please make sure to properly format your answers. All dollar figures in the answers need to include the dollar sign and any amount over 1,000 should include the comma ($2,354.67). All percentage values in the answers need to include a percentage sign (%). For all items without specific rounding instructions, round your answers to two decimal places, show both decimal places (5.06).

a. What is the mean for food and lodging for a 10-day vacation? _

b. What is the standard deviation of the distribution for the 10-day vacation?

c. What is the variance of the distribution for the 10-day vacation? __

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joaobezerra joaobezerra · Answer 1 · 2022-09-13T21:46:48+02:00

The statistical measures for the 10-day vacation are given as follows:

a) Mean: $2470.

b) Standard deviation: $189.74.

c) Variance: $²36,001.

To find the mean for n days, we take the mean amount in a single day and multiply by n.

Hence:

247 x 10 = $2470.

To find the standard deviation for n days, we take the standard deviation for a single day and multiply by the square root n.

Hence:

60 x sqrt(10) = $189.74.

The variance is the square of the standard deviation, hence:

($189.74) = $²36,001.

More can be learned about statistical measures at https://brainly.com/question/15583583

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