The equilibrium concentration of SO2(g) is 1.9
In this, the ratio of concentrations of the substancess should be on the right to the concentrations of those on the left and the same should be equivalent to the reaction
SInce
Kc = 1.7 x 108
[SO2]eq = 0.0034 M
[O2]eq = 0.0018 M
Now
Equilibrium constant,
Kc = [SO3]2/[SO2]2[O2]
, 1.7 x 108 = [SO3]2/(0.0034)2(0.0018)
[SO3] = 1.9
Hence, the equilibrium concentration of SO3(g) is 1.9 mol/L
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