contestada

What is the boiling point elevation, for a solution containing 0. 253 moles of naphthalene in 190 g of liquid benzene?

Respuesta :

The boiling point elevation is 1.6617

The given data is

0.253 of naphthalene

190 g of liquid benzene

ΔTb = Kb M

molarity = moles of solute  / kilograms of solvent

moles of naphthalene is 0.01248

molarity = 0.01248 / 0.190

             = 0.06568 M

ΔTb = Kb M

       = 2.53 × 0.6568

       = 1.6617

Hence the boiling point elevation is 1.6617

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