Given the balanced equation representing a
reaction: 4Al(s) + 30₂(g) → 2Al₂O,(s)
How many moles of oxygen react with 12 moles of aluminum?

Respuesta :

From the coefficients of the equation, we see that for every 4 moles of aluminum consumed, 3 moles of oxygen are consumed.

So, the answer is (12/4)(3) = 9 moles.