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In a group of 25 students at lunch, 10 prefer ketchup on their hamburger, 10 prefer mustard on
their hamburger, and 5 like both ketchup and mustard on their hamburger. The rest of the
students in the group prefer neither. What is the probability that a student selected from this
group will prefer ketchup or mustard on their hamburger?

Respuesta :

CoastsideDad

Answer:

15/25 or 3/5 or 60%

Step-by-step explanation:

P(K or M) = P(K) + P(M) - P(K and M)

               = [tex]\frac{10}{25}[/tex] + [tex]\frac{10}{25}[/tex] - [tex]\frac{5}{25}[/tex]

               = [tex]\frac{15}{25}[/tex]

               = .6 or 60%

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