Respuesta :

Reaction

2AgNO₃  +  Cu ⇒ Cu(NO₃)₂  +  2Ag

mol silver (Ag): 95.3 : 108 g/mol = 0.882

mol  copper nitrate (Cu(NO₃)₂): 82.9 : 187.5 g/mol = 0.441

mol Ag = 2 x mol Cu(NO₃)₂, so 0.441 being the mole basis of the reactants

mol Cu = 0.441

mass Cu = 0.441 x 63.5 g/mol = 28 g

mol AgNO₃ = 0.882

mass AgNO₃ = 0.882 x 170 g/mol = 149.94 g