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Two blocks connected by a cord passing over a small, frictionless pulley rest on frictionless planes (the figure (figure 1)).

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okpalawalter8

We have that the acceleration when going left  is mathematically given as

a = 0.671 m/s^2

Acceleration of Pulley

Let the system move leftward in direction

Hence we have tension to be

T - m1gsin53 = m1a

m2gsin30 - T = m2a

Therefore

m2gsin30 - m1gsin53.1 = a(m1+m2)

a=g(m2sin30-m1sin53.1) / (m1+m2)

a = 0.671 m/s^2

For more information on acceleration visit

https://brainly.com/question/605631

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