Respuesta :

MrRoyal

The polynomial that has the zeros when x = 5, 1/3 and -7 is [tex]P(x) = (x - 5) (x - \frac 13) (x + 7)[/tex]

Polynomial Zeros

The zeros of the polynomial are given as:

  • x = 5
  • x = 1/3
  • x = -7

Rewrite the above equations, as follows:

  • x - 5 = 0
  • x - 1/3 = 0
  • x + 7 = 0

Writing the equation

Multiply the above equations

[tex](x - 5) \times (x - \frac 13) \times (x + 7) = 0 \times 0 \times 0[/tex]

[tex](x - 5) \times (x - \frac 13) \times (x + 7) = 0[/tex]

Remove the product sign

[tex](x - 5) (x - \frac 13) (x + 7) = 0[/tex]

Rewrite the above as a function

[tex]P(x) = (x - 5) (x - \frac 13) (x + 7)[/tex]

Hence, the polynomial that has the zeros when x = 5, 1/3 and -7 is [tex]P(x) = (x - 5) (x - \frac 13) (x + 7)[/tex]

Read more about polynomials at:

https://brainly.com/question/2833285

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