guilmar10m
guilmar10m
11-01-2017
Mathematics
contestada
-16t^2+120=0. round to nearest hundredth
Respuesta :
Hi4801824552
Hi4801824552
11-01-2017
Solution:
1) Subtract 120 from both sides
-16{t}^{2}=-120
2) Divide both sides by -16
{t}^{2}=\frac{-120}{-16}
3) Two negatives make a positive
{t}^{2}=\frac{120}{16}
4) Simplify \frac{120}{16} to \frac{15}{2}
{t}^{2}=\frac{15}{2}
5) Take the square root of both sides
t=\pm \sqrt{\frac{15}{2}}
6) Simplify \sqrt{\frac{15}{2}} to \frac{\sqrt{15}}{\sqrt{2}}
t=\pm \frac{\sqrt{15}}{\sqrt{2}}
Decimal Form: ±2.738613
Done!
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