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How many grams of titanium metal can be produced if 12.5 of hydrogen gas reacts with excess titanium(IV) bromide(TiBr4)?

A. 6.25g
B. 148g
C. 47.9
D. 6.20g

Respuesta :

The mass of titanium metal formed is 148g.

The equation of the reaction is;

TiBr4(s) + 2H2(g) ------>Ti(s) + 4HBr(g)

The number of moles of hydrogen gas = 12.5 g/2.00 g/mol = 6.25 moles of hydrogen gas

If 2 moles of hydrogen gas yields 1 mole of titanium metal

6.25 moles of hydrogen gas yields 6.25 moles × 1 mole/2 moles = 3.1 moles of titanium metal

Mass of titanium metal = 3.1 moles of titanium metal × 47.8 g/mol = 148g

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