neopang neopang

09-10-2021
Mathematics

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find all natural numbers n such that 1+3+5+7+...+(2n-1) sum is divisible by 4

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Anonimity Anonimity

09-10-2021

n ∈ natural even numbers

Step-by-step explanation:

1 + 3 + 5 + 7 + … + (2n-1)

a = 1
b = 2
Uₙ = 2n - 1

sum of the first n terms :

Sₙ = n/2(a + Uₙ)

Sₙ = n/2(1 + 2n - 1)

Sₙ = n/2(2n)

Sₙ = n²

∴ so, the solution of n is all natural even numbers

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Аноним Аноним

09-10-2021

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