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If a hook can sustain a maximum withdrawal force of 250 N inthe vertical direction, determine the maximum tension, T, that can be exerted.
the vector T, points down in the fourth quadrant with the inside angle at 10 degrees.

Respuesta :

okpalawalter8

We have that the maximum tension T, that can be exerted is

[tex]T=1440N\\or T=254N[/tex]

From the question we are told that

maximum withdrawal force of 250 N

the inside angle at 10 degrees.

Generally the equation for the tension  is mathematically given as

[tex]T = 250N/sin(10) \\\\T=1440N[/tex]

We could also interpret as

[tex]T = 250N/cos(10) \\\\T=254N[/tex]

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