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You are playing a version of the roulette game, wherethe pockets arefrom 0 to 12 and even numbers are red and odd numbersare black (0 isgreen). You spin 3 times and add up the values yousee. What is theprobability that you get a total of 17 given on thefirst spin youspin a 2

Respuesta :

Using the concept of probability, it is found that there is a 0.0592 = 5.92% probability that you get a total of 17 given on the first spin you spin a 2.

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  • A probability is the number of desired outcomes divided by the number of total outcomes.
  • Since you spin a 2 on the first trial, the probability desired is equivalent to the probability of finding a sum of 15 in the next two trials.

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In each trial, there are 13 possible outcomes(pockets numbered from 0 to 12), so the total number of outcomes is:

[tex]T = 13^2 = 169[/tex]

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The desired outcomes are those who result in a sum of 15. Thus, they are:

  • (3,12), (4,11), (5,10), (6,9), (7,8), (8,7), (9,7), (10,5), (11,4), (12,3).
  • That is, 10 desired outcomes, so [tex]D = 10[/tex].

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Thus, the probability is:

[tex]p = \frac{D}{T} = \frac{10}{169} = 0.0592[/tex]

0.0592 = 5.92% probability that you get a total of 17 given on the first spin you spin a 2.

A similar problem is given at https://brainly.com/question/21444373

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