Respuesta :

Let the no be x

ATQ

[tex]\\ \sf\longmapsto 6x+11=17[/tex]

[tex]\\ \sf\longmapsto 6x=17-11[/tex]

[tex]\\ \sf\longmapsto 6x=6[/tex]

[tex]\\ \sf\longmapsto x=\dfrac{6}{6}[/tex]

[tex]\\ \sf\longmapsto x=1[/tex]

Answer:

1

Step-by-step explanation:

let the number be x

and solve it

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