By the third day of a particular week, 2 accidents have already occurred in the intersection. What is the probability that there will be less than a total of 4 accidents during that week

Respuesta :

Answer:

The right answer is "0.70".

Step-by-step explanation:

The given query seems to be incomplete. Please find below the attachment of the full query.

By using the Bayes' theorem, we get

⇒  [tex]P[(X<4)|(X \geq 2)] = \frac{P(2 \leq X < 4)}{P(X \geq 2)}[/tex]

By putting the values, we get

                                     [tex]=\frac{[P(2)+P(3)]}{[1-P(0)-P(1)]}[/tex]

                                     [tex]=\frac{(0.20+0.15)}{1-0.20-0.30}[/tex]

                                     [tex]=\frac{0.35}{0.5}[/tex]

                                     [tex]=0.70[/tex]

Ver imagen Cricetus

Answer:0.70

Step-by-step explanation: