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We can also apply the equation for residence time to a single component of a fluid, such as carbon dioxide (CO2). Assume that the residence time of CO2 in the atmosphere is six years and the mass of CO2 in the atmosphere is 3 × 1015 kilograms. If these estimates are correct, what is the mass flow rate of CO2 into and out of the atmosphere? Assume the atmosphere is at steady state. Write your answer in scientific notation, and be sure to include the correct units.

Respuesta :

Answer:

[tex]f=5*10^1^4kg/year[/tex]

Explanation:

[tex]T=m/f\\f=m/T\\f=\frac{3*10^1^5kg}{6 years}[/tex]

The mass flow rate of CO2 into and out of the atmosphere is [tex]f = 5 * 10^{14} kg/ year[/tex]

What is the method ?

[tex]T = m/f[/tex]  

Therefore, [tex]f = m/ t[/tex]

[tex]f=3 * 10^{15} / 6 years[/tex]

So, the correct answer is : [tex]f = 5 * 10^{14} kg/ year[/tex]

What is mass flow rate?

  • The mass of a substance which passes per unit of time.
  • Its unit is kilogram per second in SI units, and slug per second or pound per second in US customary units

Learn more about mass flow rate below,

https://brainly.com/question/15877818

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