Analyze the following code:
// Enter an integer Scanner input = new Scanner(System.in);
int number = input.nextInt(); if (number <= 0) System.out.println(number);
1) The if statement is wrong, because it does not have the else clause;
2) System.out.println(number); must be placed inside braces;
3) If number is zero, number is displayed;
4) If number is positive, number is displayed.
5) number entered from the input cannot be negative.

The code snippet created is supposed to take any input number from the user (positive or negative) and print it to the console if it is less than 0. In this code the IF statement does not need an else clause and will work regardless. The System.out.println() statement does not need to be inside braces since it is a simple one line statement. Therefore, the only statement in the question that is actually true would be ...

3) If number is zero, number is displayed;

MrRoyal MrRoyal · Answer 2 · 2021-07-13T09:46:41+02:00

Answer:

If number is zero, number is displayed

Explanation:

Given

The above code segment

Required

What is true about the code segment

Analyzing the options, we have:

(1) Wrong statement because there is no else clause

The above statement is not a requirement for an if statement to be valid; i.e. an if statement can stand alone in a program

Hence, (1) is false

(2) The print statement must be in { }

There is only one statement (i.e. the print statement) after the if clause. Since the statement is just one, then the print statement does not have to be in {} to be valid.

Hence, (2) is false

(3) number is displayed, if input is 0

In the analysis of the program, we have: number <=0

i.e. the if statement is true for only inputs less than 0 or 0.

Hence, number will be printed and (3) is false

(4) number is displayed for positive inputs

The valid inputs have been explained in (3) above;

Hence, (4) is false.

(5) is also false