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How do you find the perimeter of a rectangle with the dimensions

(x^2+2x-16) ft (length)
and (x+5) ft (width)

Respuesta :

ferrybukantoro

Answer:

(2x²+6x-22) ft

Step-by-step explanation:

l = (x²+2x-16) ft

and w = (x+5) ft

the Perimeter =

2(x²+2x-16) +2(x+5)

= 2x²+4x-32+2x+10

= 2x²+6x-22

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