jesuszamb3
jesuszamb3
07-12-2016
Mathematics
contestada
What's the answer ????????
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Аноним
Аноним
07-12-2016
there is a right triangle in a cone :)
we will use pythagorean theorem ;
?^2+(7.41)^2=16^2
?^2=16^2-(7.4)^2
if we both side square root;
[tex] \sqrt{?^2}= \sqrt{16^2-(7.4)^2} \\ ?= \sqrt{16^2-(7.4)^2}[/tex]
So the answer is 4th option :)
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