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PLEASE HELP MAX POINTS AND BRAINLIEST!!!Find the length of the longest nail that could fit entirely within a cylindrical can of radius 2 inches and height of 6 inches.​

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thebecks

Answer:

a 7.2 inch nail

Step-by-step explanation:

using the Pythagorean theorem:

the diagonal distance of a 6" height and a 2" radius (4" diameter) would be:

D² = 6² + 4² = 36 + 16 = 52

D = √52 = 7.21 inches

Find diagonal that's the answer

Use Pythagorean theorem

  • H²=P²+B²
  • H²=6²+(2+2)²
  • H²=36+16
  • H²=52
  • H=√52

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