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A gas at a temperature of 300 K occupies a 5 L flexible container at a pressure of 150 kPa. What volume will it occupy at STP?

Respuesta :

6.73 L

This one requires the combined gas law.

P1V1/T1 = P2V2/T2

P1 = 150 kPa = 1.48 atm

V1 = 5 L

T1 = 300 K

P2 = 1 atm

V2 = This is what we’re solving for.

T2 = 273 K

P2 and T2 are based on the conditions of STP. I also changed P1 to atm to keep the units consistent.

Solve the equation for V2:

V2 = P1V1T2 / T1P2

V2 = (1.48 atm)(5 L)(273 K) / (300 K)(1 atm) = 6.73 L

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