Answer:
y = 2x^2 + 4x - 2
Step-by-step explanation:
y=2(x+1)^(2)-4 is in vertex form. We want the same equation in standard form, which looks like y = ax^2 + bx + c.
Perform the indicated multiplication (squaring of x + 1):
y = 2(x^2 + 2x + 1) - 4, or
y = 2x^2 + 4x + 2 - 4, or
y = 2x^2 + 4x - 2 This is in the standard form of a quadatic.
