Answer:
The ball will take approximately 2.165 seconds.
Step-by-step explanation:
The height of the ball is represented by the function [tex]h(t) = -16\cdot t^{2}+75[/tex], the time taken by the ball to hit the ground is a value of [tex]t[/tex] such that [tex]h(t) = 0[/tex], we proceed to solve the following equation for [tex]t[/tex]:
[tex]-16\cdot t^{2}+75 = 0[/tex] (1)
[tex]16\cdot t^{2} = 75[/tex]
[tex]t = \sqrt{\frac{75}{16} }[/tex]
[tex]t \approx 2.165\,s[/tex]
The ball will take approximately 2.165 seconds.
